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Instructor test bank 2023 verified and updated.
- Exam (elaborations) • 232 pages • 2023
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Instructor test bank 2023 verified and updated. 
 
By TECHGRADES. 
 
 
 
 
 
 1-Advanced Engineering Electromagnetics by Constantine Balanis 2-Antenna Theory and Design, 2ed+1ed, by Warren Stutzman 3-Circuit Design with VHDL by Volnei A. Pedroni 4-Convex Optimization by Stephen Boyd and Lieven Vandenberghe 5-Digital signal processing 2+1ed, by Sanjit K. Mitra 6-Partial differential equations, lecture notes by Neta 7-Fundamental Methods of Mathematical Economics 4ed, by Alpha C. Chiang 8-C++ How ...
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Test Bank For Pediatric Physical Examination An Illustrated Handbook 3rd Edition by Karen G. Duderstadt 9780323476508 Chapter 1-20 Complete Guide
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Test Bank For Pediatric Physical Examination An Illustrated Handbook 3rd Edition by Karen G. Duderstadt 6508 Chapter 1-20 Complete GuideIf your request was not in my List, Feel free and email me ,I will try to help. We Can provide 
Customers Any of these Items : 1- Solution manuals(End of chapters problem`s Solutions) SM 
2-Case Solutions CASE SM 3-Testbank (Multiple Choice Questions + Answers) TB 4- 
Powerpoints ppt 5-Lecture Notes LN 6-Instructors Manual IMSolution manual Testbank Case 
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list of books with solution manual
- Summary • 242 pages • 2022
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list of books with solution manualIf your request was not in my List, Feel free and email me ,I will try to help. We Can provide Customers Any of these Items : 1- Solution manuals(End of chapters problem`s Solutions) SM 2-Case Solutions CASE SM 3-Testbank (Multiple Choice Questions + Answers) TB 4-Powerpoints ppt 5-Lecture Notes LN 6-Instructors Manual IMSolution manual Testbank Case Study Powerpoints Supplements Are Available Now 
 
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SOLUTION MANUAL ENGINEERING ELECTROMAGNETICS BY WILLIAM H. HAYT 8TH EDITION COMPLETE CHAPTERS
- Exam (elaborations) • 259 pages • 2022
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CHAPTER 1 
1.1. Given the vectors M = −10ax + 4ay − 8az and N = 8ax + 7ay − 2az, find: 
a) a unit vector in the direction of −M + 2N. 
−M + 2N = 10ax − 4ay + 8az + 16ax + 14ay − 4az = (26, 10, 4) 
Thus 
a = 
(26, 10, 4) 
|(26, 10, 4)| 
= (0.92, 0.36, 0.14) 
b) the magnitude of 5ax + N − 3M: 
(5, 0, 0) + (8, 7, −2) − (−30, 12, −24) = (43, −5, 22), and |(43, −5, 22)| = 48.6. 
c) |M||2N|(M + N): 
|(−10, 4, −8)||(16, 14, −4)|(−2, 11, −10) = (13.4)(21.6)(−2, 11...
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SOLUTION MANUAL ENGINEERING ELECTROMAGNETICS BY WILLIAM H. HAYT 8TH EDITION COMPLETE CHAPTERS
- Exam (elaborations) • 259 pages • 2022
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CHAPTER 1 
1.1. Given the vectors M = −10ax + 4ay − 8az and N = 8ax + 7ay − 2az, find: 
a) a unit vector in the direction of −M + 2N. 
−M + 2N = 10ax − 4ay + 8az + 16ax + 14ay − 4az = (26, 10, 4) 
Thus 
a = 
(26, 10, 4) 
|(26, 10, 4)| 
= (0.92, 0.36, 0.14) 
b) the magnitude of 5ax + N − 3M: 
(5, 0, 0) + (8, 7, −2) − (−30, 12, −24) = (43, −5, 22), and |(43, −5, 22)| = 48.6. 
c) |M||2N|(M + N): 
|(−10, 4, −8)||(16, 14, −4)|(−2, 11, −10) = (13.4)(21.6)(−2, 11...
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Electrostatics
- Class notes • 154 pages • 2024
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Electrostatics is the theory of the electric field in conditions in which its behavior is independent of magnetic fields, including The electric field associated with fixed distributions of electric charge Capacitance (the ability of a structure to store energy in an electric field) The energy associated with the electrostatic field Steady current induced in a conducting material in the presence of an electrostatic field (essentially, Ohm’s Law) The term “static” refers to the fact that t...
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Engineering_Electromagnetics___7th_Edition___William_H._Hayt___Solution_Manual
- Exam (elaborations) • 250 pages • 2022
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Engineering_Electromagnetics___7th_Edition___William_H._Hayt___Solution_Manual 
Given the vectors M = −10ax + 4ay − 8az and N = 8ax + 7ay − 2az, find: 
a) a unit vector in the direction of −M + 2N. 
−M + 2N = 10ax − 4ay + 8az + 16ax + 14ay − 4az = (26, 10, 4) 
Thus 
 
a = (26, 10, 4) 
|(26, 10, 4)| 
 
= (0.92, 0.36, 0.14) 
 
b) the magnitude of 5ax + N − 3M: 
(5, 0, 0) + (8, 7, −2) − (−30, 12, −24) = (43, −5, 22), and |(43, −5, 22)| = 48.6. 
c) |M||2N|(M + N): 
|(−...
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Engineering_Electromagnetics___7th_Edition___William_H._Hayt___Solution_Manua
- Exam (elaborations) • 250 pages • 2022
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- $15.98
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1.1. Given the vectors M = −10ax + 4ay − 8az and N = 8ax + 7ay − 2az, find: 
a) a unit vector in the direction of −M + 2N. 
−M + 2N = 10ax − 4ay + 8az + 16ax + 14ay − 4az = (26, 10, 4) 
Thus 
a = (26, 10, 4) 
|(26, 10, 4)| 
= (0.92, 0.36, 0.14) 
b) the magnitude of 5ax + N − 3M: 
(5, 0, 0) + (8, 7, −2) − (−30, 12, −24) = (43, −5, 22), and |(43, −5, 22)| = 48.6. 
c) |M||2N|(M + N): 
|(−10, 4, −8)||(16, 14, −4)|(−2, 11, −10) = (13.4)(21.6)(−2, 11, −10) 
= ...
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solutions_manual_engineering_electromagnetics_by_hayt_8th_edition
- Exam (elaborations) • 259 pages • 2022
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- $15.49
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1.1. Given the vectors M = −10ax + 4ay − 8az and N = 8ax + 7ay − 2az, find: 
a) a unit vector in the direction of −M + 2N. 
−M + 2N = 10ax − 4ay + 8az + 16ax + 14ay − 4az = (26, 10, 4) 
Thus 
a = 
(26, 10, 4) 
|(26, 10, 4)| 
= (0.92, 0.36, 0.14) 
b) the magnitude of 5ax + N − 3M: 
(5, 0, 0) + (8, 7, −2) − (−30, 12, −24) = (43, −5, 22), and |(43, −5, 22)| = 48.6. 
c) |M||2N|(M + N): 
|(−10, 4, −8)||(16, 14, −4)|(−2, 11, −10) = (13.4)(21.6)(−2, 11, −10) 
=...
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